spw812 spw812
  • 04-03-2019
  • Mathematics
contestada

solution set for 5x + 38
[tex] \leqslant [/tex]
is less than 4(2-5x)​

Respuesta :

jamuuj jamuuj
  • 04-03-2019

Answer:

x ≤ -6/5

Step-by-step explanation:

5x + 38 ≤ 4 (2 - 5x)

5x + 38 ≤ 8 - 20x

5x + 20x ≤ 8 - 38

25x ≤ -30

x ≤ -30÷25

x ≤ -6/5

Answer Link
zainebamir540
zainebamir540 zainebamir540
  • 04-03-2019

Answer:

{ x / x ≤ -6/5 } is the solution set of the given inequality.

Step-by-step explanation:

We have given an inequality :

5x + 38 <= 4(2-5x)​

We have to find  the solution set of the given inequality.

So,

5x + 38 ≤ 4(2-5x)​  

5x + 38 ≤ 8 - 20x

Combining like terms we get,

5x +20x ≤ 8 -38

25x ≤ -30

x ≤ -6/5

{ x / x ≤ -6/5 } is the solution set of the given inequality.

Answer Link

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