zanaplen27
zanaplen27 zanaplen27
  • 15-03-2019
  • Mathematics
contestada

Given a≠±b and (a^2−b^2)/(a+b)=12, find a−b.

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jcherry99
jcherry99 jcherry99
  • 15-03-2019

Answer:

Step-by-step explanation:

a^2 - b^2 factors into (a + b)(a - b)

So now you have

(a + b)(a - b)

==========     = 12

(a + b)

You are given that a <>   b

So a + b cancels with (a + b) on the top.

a - b = 12

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Kamikazeminem
Kamikazeminem Kamikazeminem
  • 15-03-2019

[tex]a\neq\pm b\Rightarrow \frac{ ( {a}^{2} - {b}^{2} ) }{a + b} = 12\Leftrightarrow \frac{(a - b)(a + b)}{a + b} = 12\Leftrightarrow a - b = 12[/tex]

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