[tex]\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x[/tex]

can someone explain how to do this i dont get fractions

Question

01-09-2019
Mathematics

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[tex]\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x[/tex]

can someone explain how to do this i dont get fractions

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micael1223 micael1223 · Answer 1 · 2019-09-01T23:16:20+02:00

micael1223 micael1223

01-09-2019

Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x
≥
−
3
x
≥
-
3
Interval Notation:
[
−
3
,
∞
)

Answer Link

bhadiexjen bhadiexjen · Answer 2 · 2019-09-01T23:17:37+02:00

bhadiexjen bhadiexjen

01-09-2019

They are saying that 1/6 - 2/9x is greater than 1/2

1/2=50%
1/6= 16.6%
2/9x=18%

16%-18% is not greater so therefore this answer is false

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[tex]\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x[/tex]can someone explain how to do this i dont get fractions

Respuesta :

Otras preguntas

[tex]\frac{1}{2} \geq -\frac{1}{6} -\frac{2}{9} x[/tex]

can someone explain how to do this i dont get fractions