Answer:
The point P(1,-3) is not a solution to the system.
Step-by-step explanation:
Given [tex]\left \{ {{y<x-1} \atop {y>-x+2}} \right.[/tex]
Let a point be P(1,-3)
Here x = 1 ; y = -3
Substituting the values of x,y in the function
[tex]\left \{ {{y<x-1} \atop {y>-x+2}} \right.[/tex]
For y<x-1
-3 < 1-1
-3<0 (True)
now for,
y>-x+2
-3 > -1 + 2
-3 > 1 (False)
Hence the point is not a solution to the system.
