ElliVanderJagt ElliVanderJagt
  • 01-04-2020
  • Mathematics
contestada

For the function ​f(x)=x^{2} + 4x - 32 solve the following.​

f(x)=0

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 01-04-2020

Answer:

x=-8                 x=4

Step-by-step explanation:

x^2 + 4x - 32

We want to set this equal to zero

x^{2} + 4x - 32 =0

Factor this equation

what two numbers multiply together to equal -32 and add together to equal4

8 * -4 = -32

8+ -4 = 4

(x+8) ( x-4) =0

Using the zero product property

x+8  =0       x-4 =0

x+8-8=0-8     x-4+4=0+4

x=-8                 x=4

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