Answer:
7/12 probability of randomly choosing a lunch bag that contains either an apple or banana
Step-by-step explanation:
We have these following probabilities:
1/4 probability that a lunch bag contains an apple.
1/3 probability that a lunch bag contains a banana.
What is the probability of randomly choosing a lunch bag that contains either an apple or banana?
[tex]P = \frac{1}{4} + \frac{1}{3} = \frac{3 + 4}{12} = \frac{7}{12}[/tex]
7/12 probability of randomly choosing a lunch bag that contains either an apple or banana
