NegativeCreep7360 NegativeCreep7360
  • 13-05-2020
  • Mathematics
contestada

When a 19.2-g sample of KCN dissolves in 65.0 g of water in a calorimeter, the temperature drops from 28.1 (C) to 15.4 (C). Calculate DH for the process

Respuesta :

codiepienagoya codiepienagoya
  • 22-05-2020

Answer:

The answer is "[tex]\bold{\ 15.4 \frac{kj}{mol}} \\[/tex] ".

Step-by-step explanation:

Equation:

[tex]KCN(s) \rightarrow K^+(aq)+CN^-(aq) \ \ \ \[/tex]  ΔH =?

[tex]\ Q = (84.2) (4.184)(-12.7) \\\\\ Q = -4474\\\\\ Q_(r \times r) = \frac{+ 4.474 kj}{0.29mol} \\\\\ Q= 15.4 \frac{kj}{mol}[/tex]

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