hun5nykashDah hun5nykashDah

02-09-2016
Mathematics

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find the average value of the funtion fx=sec^2x on the interval [0,pi/4]

Respuesta :

HomertheGenius HomertheGenius

10-09-2016

Average value:
[tex] \frac{1}{ \frac{ \pi }{4} -0} * \int\limits^a_b { sec^{2}x } \, dx [/tex]
a = π / 4 , b = 0
= 4/π · tan x = 4/π · ( tan π/4 - tan 0 ) = 4/π · ( 1 - 0 ) = 4/π

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