samisheng2008
samisheng2008 samisheng2008
  • 04-07-2020
  • Mathematics
contestada

3k(x+2)+2 = 5x+8
How do I solve for k while keeping x smaller then 3?

Respuesta :

mhanifa
mhanifa mhanifa
  • 04-07-2020

Answer:

k=(5x+6)/(3x+6) and k<3/5

Step-by-step explanation:

  • 3k(x+2)+2 = 5x+8
  • 3k(x+2)=5x+6
  • 3k=(5x+6)/(x+2)
  • k=(5x+6)/(3x+6)

it is solved for k

and considering the condition for x<3:

  • 3k(x+2)+2 = 5x+8
  • 3kx+6k=5x+6
  • (5-3k)x=6k-6
  • x= (6k-6)/(5-3k)
  • x<3 ⇒ (6k-6)/(5-3k)<3 ⇒  6k-6<15-9k ⇒ 15k<9 ⇒ k<9/15 ⇒ k<3/5

So,

k=(5x+6)/(3x+6) and k<3/5

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