[tex]\huge{\fbox{\sf{n=5 }}}[/tex]
Step 1:
[tex]⇒ {2}^{n - 5} \times {5}^{n - 4} = 5[/tex]
Step 2:
[tex] ⇒{2}^{n - 5} \times {5}^{n - 4} = {5}^{1} \times {2}^{0} [/tex]
On comparing values we get:
Taking:
[tex] {2}^{n - 5} = {2}^{0} [/tex]
n-5=0
n=5✓
or
Taking:
[tex] {5}^{n - 4} = {5}^{1} [/tex]
n-4=1
n=5✓
