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01-11-2016
Physics

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A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

Respuesta :

syed514 syed514

03-11-2016

...
use this equation
F delta(t) = m delta(v)
F (0.50) = 3.6 (3.3)
F = 23.8 N

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