devinmoore2963 devinmoore2963
  • 01-04-2021
  • Physics
contestada

Encontrar la cantidad de movimiento de una partícula de 3,05Kg que se mueve a una velocidad de 56m/s.

Respuesta :

Lanuel
Lanuel Lanuel
  • 01-04-2021

Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

[tex] Momento = masa * velocidad [/tex]

Sustituyendo en la fórmula, tenemos;

[tex] Momento = 3.05 * 56 [/tex]

Momento = 170.8 Kgm/s

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