Answer:
156.78 °C
Explanation:
First we convert 9.8 grams of NH₃ into moles, using its molar mass:
- 9.8 g ÷ 17 g/mol = 0.576 mol
Then we can use the PV=nRT formula to calculate the temperature, where:
- P = 98.3 kPa ⇒ 98.3/101 = 0.967 atm
- R = 0.082 atm·L·mol⁻¹·K⁻¹
We input the data:
- 0.967 atm * 21.0 L = 0.576 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T
And solve for T:
Finally we convert 429.94 K to °C:
- 429.94 - 273.16 = 156.78 °C
