Respuesta :

MrRoyal

Answer:

[tex]\frac{y^8}{x^{10}}[/tex]

Step-by-step explanation:

Given

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Required

The equivalent

Apply law of indices to the inner bracket

[tex](x^{-4--9}y^{1 -5})^{-2}[/tex]

[tex](x^{5}y^{-4})^{-2}[/tex]

Rewrite as:

[tex]\frac{1}{(x^{5}y^{-4})^2}[/tex]

Expand

[tex]\frac{1}{(x^{5*2}y^{-4*2})}[/tex]

[tex]\frac{1}{(x^{10}y^{-8})}[/tex]

Apply law of indices

[tex]\frac{y^8}{x^{10}}[/tex]

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