Answer:
Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i
Step-by-step explanation:
[tex]x^{2} - 4x + 5 =0[/tex]
( [tex]4[/tex]± [tex]\sqrt{16 - 4*1*5}[/tex] ) / [tex]2[/tex] = (
x1= 2+i
x2= 2-i
[tex]2x^{2} +6x + 5 =0[/tex]
( [tex]-6[/tex] ± [tex]\sqrt{36 - 4*2*5}[/tex] ) / [tex]4[/tex] = (-6 ± [tex]\sqrt{-4}[/tex] )/4= (-3 ± i)/2
x1 = -3/2 +i
x2 = -3/2 -i
