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adenreimer2028

Answer:the radius of fifth Bohr orbital of hydrogen is 1.3225x10^-9

Explanation:

Let's see

According to bohrs model

[tex]\\ \rm\Rrightarrow r\propto n^2/Z^2[/tex]

[tex]\\ \rm\Rrightarrow r= r_on^2/Z^2[/tex]

[tex]\\ \rm\Rrightarrow r=0.529\times \dfrac{5^2}{1^2}[/tex]

[tex]\\ \rm\Rrightarrow r=0.529(25)[/tex]

[tex]\\ \rm\Rrightarrow r=1.32nm[/tex]

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