Given that the linear expansion of the pipe is 12×10¯⁶ K¯¹, the pipe extends by 0.024 mm
Data obtained from the question
- Original length (L₁) = 100 mm
- Change in temperature (ΔT) = 20 K
- Coefficient of expansion (α) = 12×10¯⁶ K¯¹
- Change in length (ΔL) =?
How to determine the new diameter
α = ΔL / L₁ΔT
12×10¯⁶ = ΔL / (100 × 20)
12×10¯⁶ = ΔL / 2000
Cross multiply
ΔL = 12×10¯⁶ × 2000
ΔL = 0.024 mm
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