You dissolve 0.50 moles of Nil in 0.40L of water. The resulting concentration is 1.3M.You increase the water in the solution until you have 0.80L. What is the new concentration?

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AbdurraheemG535401 AbdurraheemG535401

03-11-2022
Chemistry

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You dissolve 0.50 moles of Nil in 0.40L of water. The resulting concentration is 1.3M.You increase the water in the solution until you have 0.80L. What is the new concentration?

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KenseyY703978 KenseyY703978 · Answer 1 · 2022-11-03T06:06:36+01:00

In this question, we have a dilution situation, in which we have an initial concentration of the substance, 1.3M and an initial volume 0.40L, but after a while, we have now a volume of 0.80 L and a new concentration, we will be using the Dilution formula:

M1V1 = M2V2

We have:

M1 = 1.3 M

V1 = 0.40 L

M2 = ?

V2 = 0.80 L

Now we will add these values into the formula:

1.3 * 0.40 = 0.80 * M2

0.52 = 0.80M2

M2 = 0.65 M, this will be the new concentration of the substance after adding more water