IfeomaL238958 IfeomaL238958
  • 03-11-2022
  • Mathematics
contestada

sin 0 = 1. Find tan 8.A.404141OB. 49O C. 40D.409e

sin 0 1 Find tan 8A404141OB 49O C 40D409e class=

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EnnaJ574799 EnnaJ574799
  • 03-11-2022
[tex]\begin{gathered} If\text{ }sin\theta=\frac{9}{41} \\ \\ \end{gathered}[/tex]

Because sine is opposite side/ hypotenuse. tangent = opposite angle / adjacent, so we need to find the adjacent side using Pitagora's theorem

[tex]\begin{gathered} c^2=a^2+b^2 \\ 41^2=9^2+b^2 \\ 1681\text{ - }81=b^2 \\ \sqrt{1600}=b \\ 40=b \end{gathered}[/tex]

And now we find tangent.

[tex]tan\theta=\frac{oppositeside}{adjacentside}=\frac{9}{40}[/tex]

So, the correct option is C

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