The expression we have is:
[tex]f(x)=9-(x+3)^2[/tex]
We need to compare this expression with the Vertex form of the quadratic equation:
[tex]f(x)=a(x-h)^2+k[/tex]
Where the vertex is at (h,k).
We rewrite our expression as follows:
[tex]f(x)=-(x-(-3))^2+9[/tex]
And we can see that h=-3, and k=9. Thus, the vertex of this quadratic function is at:
[tex](-3,9)[/tex]
Also, since we have a negative sign along side the x, that means that the parabola opens down.
And the correct result is:
Option C
